Quote from: LouScheffer on 11/13/2022 01:17 amWith this flight we can re-calibrate the loss of payload for recoverability. This flight staged at 9777 km/hr = 2715 m/s. The preceding G33/G34 flight (with recovery) staged at 8340 km/hr = 2316 m/s. Thus the first stage provided roughly 400 m/s more (roughly because the differing payload masses will have some small effect on first stage dV).Now making the usual second stage assumptions (fuel = 107t, empty mass + residual = 5.5t, ISP = 348), then how much can you increase the payload from the nominal 5.5t if the second stage needs to produce 400 m/s less? Turns out it's 7.03t. So any orbit the recoverable rocket can reach with a 5.5t payload, the expendable one can reach with a 7.03t payload.A 5.5t payload is 78% of a 7.03t payload, so the F9 Block 5 loses 22% of its GTO payload when recovering the first stage.Doesn't match the SpaceX claims of 8.3 tonnes GTO and 22.8 tonnes LEO, which date back to the start of Block 5 I think. Maybe they gave up payload to beef up the fairings for sea recovery? - Ed Kyle
With this flight we can re-calibrate the loss of payload for recoverability. This flight staged at 9777 km/hr = 2715 m/s. The preceding G33/G34 flight (with recovery) staged at 8340 km/hr = 2316 m/s. Thus the first stage provided roughly 400 m/s more (roughly because the differing payload masses will have some small effect on first stage dV).Now making the usual second stage assumptions (fuel = 107t, empty mass + residual = 5.5t, ISP = 348), then how much can you increase the payload from the nominal 5.5t if the second stage needs to produce 400 m/s less? Turns out it's 7.03t. So any orbit the recoverable rocket can reach with a 5.5t payload, the expendable one can reach with a 7.03t payload.A 5.5t payload is 78% of a 7.03t payload, so the F9 Block 5 loses 22% of its GTO payload when recovering the first stage.
Quote from: LouScheffer on 11/13/2022 01:17 amWith this flight we can re-calibrate the loss of payload for recoverability. This flight staged at 9777 km/hr = 2715 m/s. The preceding G33/G34 flight (with recovery) staged at 8340 km/hr = 2316 m/s. Thus the first stage provided roughly 400 m/s more (roughly because the differing payload masses will have some small effect on first stage dV).Now making the usual second stage assumptions (fuel = 107t, empty mass + residual = 5.5t, ISP = 348), then how much can you increase the payload from the nominal 5.5t if the second stage needs to produce 400 m/s less? Turns out it's 7.03t. So any orbit the recoverable rocket can reach with a 5.5t payload, the expendable one can reach with a 7.03t payload.A 5.5t payload is 78% of a 7.03t payload, so the F9 Block 5 loses 22% of its GTO payload when recovering the first stage.Doesn't match the SpaceX claims of 8.3 tonnes GTO and 22.8 tonnes LEO, which date back to the start of Block 5 I think. Maybe they gave up payload to beef up the fairings for sea recovery?
Quote from: edkyle99 on 11/13/2022 04:28 pmQuote from: LouScheffer on 11/13/2022 01:17 amWith this flight we can re-calibrate the loss of payload for recoverability. This flight staged at 9777 km/hr = 2715 m/s. The preceding G33/G34 flight (with recovery) staged at 8340 km/hr = 2316 m/s. Thus the first stage provided roughly 400 m/s more (roughly because the differing payload masses will have some small effect on first stage dV).Now making the usual second stage assumptions (fuel = 107t, empty mass + residual = 5.5t, ISP = 348), then how much can you increase the payload from the nominal 5.5t if the second stage needs to produce 400 m/s less? Turns out it's 7.03t. So any orbit the recoverable rocket can reach with a 5.5t payload, the expendable one can reach with a 7.03t payload.A 5.5t payload is 78% of a 7.03t payload, so the F9 Block 5 loses 22% of its GTO payload when recovering the first stage.Doesn't match the SpaceX claims of 8.3 tonnes GTO and 22.8 tonnes LEO, which date back to the start of Block 5 I think. Maybe they gave up payload to beef up the fairings for sea recovery? - Ed Kyleof course it does not match - these are different GTOs:The original claim by SpaceX - "8.3 t to GTO" - implies GTO(-1800 m/s)In this flight the payload was delivered to substantially *higher* GTO ~ -1600 m/s
Well in terms of expendable F9, this mission performed better than the last time they tried the same. For reference, Amos 17 went into a GTO-1784 vs GTO-1611 achieved on this launch. Would be interesting to compare the telemetry from both missions... *wink wink*
That gets close to GTO-1500 from French Guiana
Quote from: Alexphysics on 11/13/2022 05:37 pmWell in terms of expendable F9, this mission performed better than the last time they tried the same. For reference, Amos 17 went into a GTO-1784 vs GTO-1611 achieved on this launch. Would be interesting to compare the telemetry from both missions... *wink wink*The payloads for AMOS-17 and G31-32 were the same, at 6,500kg. The AMOS-17 booster profile was unusual because there was no throttle up after MaxQ, and so gravity losses would have been a little higher. MECOs were at 2644 and 2716m/s respectively.Second stage burn times:MissionLEO sGTO sAMOS-1731561G31-3230871So, the G31-32 second stage burn to LEO was 7s shorter, and her (lower throttle) burn to GTO was 10s longer.
I have a question:Why would the second burn of the G31-32 second stage be so delayed when compared to that for AMOS-17?The general principle is that this burn should occur over the equator.However, as the dosnrange distances are equal to the resolution of the graph, a difference in timing would equate to a difference in downrange distance, longitude, and, most significantly, lattitude.Is there a detail in the data that I am missing that allows both to be over the Equator?If not, why would this be chosen when it appears to be other than optimal?
I thought Galaxy 31/Galaxy 32 weighed 6.6 tons.
Please can someone remind me (or point at an explanation) of what the GTO-xxxx numbers mean?
Quote from: litton4 on 11/14/2022 11:11 amPlease can someone remind me (or point at an explanation) of what the GTO-xxxx numbers mean?Sure, the XXXX is the number of m/s left to get into geosynchronous orbit, so smaller numbers are better. It's a combination of two tasks - to circularize the orbit at geosynchronous height, and to remove any remaining inclination from the transfer orbit. As an example, a GTO with a GEO apogee from the Cape is about GTO-1800, whereas a GTO with GEO apogee from French Guiana is typically about GTO-1500, since the spacecraft has less inclination to remove.If your rocket has more dV than needed to simply reach GTO apogee, you can spend it by increasing the apogee above geosynchronous (which makes the plane change cheaper, by reducing the inclination cost), or reducing the inclination of the transfer orbit.
Quote from: litton4 on 11/14/2022 11:11 amPlease can someone remind me (or point at an explanation) of what the GTO-xxxx numbers mean?Sure, the XXXX is the number of m/s left to get into geosynchronous orbit, so smaller numbers are better. It's a combination of two tasks - to circularize the orbit at geosynchronous height, and to remove any remaining inclination from the transfer orbit. As an example, a GTO with a GEO apogee from the Cape is about GTO-1800, whereas a GTO with GEO apogee from French Guiana is typically about GTO-1500, since the spacecraft has less inclination to remove.
Still only 2 objects cataloged from the launch (although there is currently a gap, 54245, which could be the third object).It seems unlikely that the second stage was deorbited given the performance concerns, so I assume the third object will eventually show up.
Bob is due to arrive at Port Canaveral at midnight tonight with the fairing from Galaxy 31 & 32.