Author Topic: Planck Spherical Unit structure of space and quantum gravity (LQG)  (Read 5032 times)

Let me just give you a hypothesis about quantum gravity, and show you how to solve for a black hole's mass using a simple equation using quantized space at the planck length, a form of Loop Quantum Gravity.


You know how you can calculate the entropy of a black hole by tiling planck units on it's surface the Bekenstein–Hawking formula


Let me show you an interpretation of quantum gravity that at first seems way too easy to believe.


First, use a spherical harmonic oscillator of the planck length diameter and the planck mass energy, essentially a black hole photon - instead of the typical planck area l^2 and volume `l^3`, this will be radius =
Quote
planck length / 2
.


Using this definition, it would have a volume of:
Quote
2.2104 x 10^-99 cm^3


Such a sphere will have an equatorial plane circle of 
Quote
2.0151538 x 10^-66 cm^3
.


Let's take well known black hole Cygnus X-1


Radius:
Quote
~2.5 x 10^6 cm
.


With this radius, the amount of planck area's that fit on the surface area (equatorial plane) will be
Quote
3.838399x10^79


Now to calculate the amount of spherical oscillators that fit in the volume
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2.960912x10^118


Now let's divide the volume oscillators through the surface units, (a generalization of the holographic principle) and multiply by the planck mass


2.960912x10^118 / 3.838399x10^79  * planck mass =
Quote
1.679x10^34 gram


Using the Schwarzchild equation for a black hole of the same radius, we yield


(Had to use wolframs mass->radius shwarzchild calculator, but it comes out exactly the same)Here


This is defining a holographic/information theory approach to mass using quantized space.


So I believe that the vacuum IS the planck density, made up of overlapping planck spherical units of the planck mass (John Wheeler's mass without mass using geons (gravitational electromagnetic entities, enough field energy to keep together gravitationally).


But this isn't the end.


We can do the same with a flip to the equation, by hypothesizing that the proton is the fundamental holographic length of our Universe.


(See Scott Funkhauser's work on a fundamental holographic length of our Universe based on our Universe's size [he finds that it would be the diameter of a nucleon])
https://arxiv.org/ftp/physics/papers/0701/0701289.pdf


So the equation for the proton, instead of being volume / surface * planck mass, will be (surface / volume * 2*planck mass)


Let's try it - first calculate how much in volume * planck mass


Proton charge radius:
Quote
.8755 x 10^-16 m



Proton volume with given radius:
Quote
2.831 * 10^-45 m^3


Planck length diameter sphere volume:
Quote
2.21 * 10^-99 cm^3


Divide them and multiply by planck mass


Quote
((2.831 * 10^-45 m^3) / (2.21 * 10^-99 cm^3)) * planck mass
wolfram


Yields:
Quote
1.281 * 10^60 * planck mass = 2.788 * 10^55 grams
.


(Note, this is very close to the currently estimated mass of the Universe, hint) - simply dividing the proton by the planck density of space using spherical oscillators yields the mass of the observable universe.


>Next divide surface / volume


And here is calculating the proton rest mass via these same principles but applying the holographic principle
Quote
planck masses that fit on surface / planck spheres in volume


Surface Plancks on proton area with proton charge radius  :
Quote
4.71 * 10^40


Surface Plancks times planck mass:
Quote
1.02656 * 10^36 gram


That is the mass of the 'surface horizon' of the proton.


Now all we have to do is divide by the plancks that would fit inside:


 
Quote
2 * (surface horizon mass / planck units in volume)




Quote
2 * (1.02656 * 10^36 gram / 1.2804 * 10^60) = 1.603498 * 10 ^-24 grams
http://www.wolframalpha.com/input/?i=2+*+%284.7116551*10%5E40+*+planck+mass%29+%2F+1.2804*10%5E60)


How could this work


Obviously this means that the vast, vast majority of massinformation in the proton is non-local.


If the structure of space itself was made up of overlapping planck spherical units of the planck mass, we would have a Bose Einstein Condensate of space, implicating that the surface horizon of these black holes are using this to transfer massinformation instantly outward, i.e. the majority of mass is nonlocal due to Einsten-Rosen bridge wormholes (implicating EP=EPR)




There is a _ton_ more to this theory, including satisfying the strong nuclear force by calculating the attractive force of a spinning black hole proton at < 1 planck length from another proton (~10^14 grams, Funkhausers estimated holographic mass), and this would exactly satisfy the strong force if the proton was spinning at C (we've already found black holes spinning very, very near c) - whats more is that this mass dilation would almost  instantly drop to the rest mass at >1 planck length away - torquing space causing the gravitaitonal<>strong force coupling constant.


So the planck density of space is real. There is a specific geometry of packing overlapping planck spherical units that allow it to be polarizable, which when polarized, yields mass - while the vast majority appears to us as empty.


>We see that the question [posed] is not, "Why is gravity so feeble?" but rather, "Why is the proton's mass so small?" For in natural (Planck) units, the strength of gravity simply is what it is, a primary quantity, while the proton's mass is the tiny number [1/(13 quintillion)].[14]  [Frank Wilczek](https://en.wikipedia.org/wiki/Planck_units#Cosmology)




Yes, this changes a ton of fundamental assumptions we hold in physics. Yes, it implicates that gravity curls as it curves (like a vortex). Yes, it implicates a bose-eisntein condensate of space. Yes, protons aren't supposed to 'orbit'. There are explanations for all of these, so fire away


IF the EMDrive is creating a pressure gradiant in the vacuum by causing a symmetry break/polarizing vacuum, well then the EMDrive _is_ pushing against the quantum vacuum



The 2013 muonic hydrogen charge radius yields a mass that's within .000366*10^-13 cm


Please, ignore the author before you dismiss this work, it will revolutionize physics.
« Last Edit: 11/21/2016 02:40 pm by d8_thc »

Offline sanman

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Yes, this changes a ton of fundamental assumptions we hold in physics. Yes, it implicates that gravity curls as it curves (like a vortex). Yes, it implicates a bose-eisntein condensate of space. Yes, protons aren't supposed to 'orbit'. There are explanations for all of these, so fire away


IF the EMDrive is creating a pressure gradiant in the vacuum by causing a symmetry break/polarizing vacuum, well then the EMDrive _is_ pushing against the quantum vacuum


How is your conjecture physically testable/provable/falsifiable?

Way back in university I remember being told about the "permittivity of free space" - aka. the "dielectric constant"

https://en.wikipedia.org/wiki/Relative_permittivity#Measurement

So is this vacuum permittivity being changed by both the cavity and the electric field (vacuum polarization) inside it? Is it resulting in better coupling for momentum transfer with resonant photons, that would be superior to a photon rocket?

Based on what you've said, what optimizations would be suggested for the EMdrive, to maximize measurable thrust relative to the power input?

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