...OK, this will be the last post I will have on geometry.
Your calculation is incorrect
Since 10.5-6.25 = 4.25
that gives a base for the right angle triangle of 4.25.
Hence a cone half angle of 33 degrees would give a height of 4.25/Tan[33 degrees] = 6.54 instead of 1.38
RE WolfofWallStreet comments on buoyancy in TT's tests: TT has stated (almost as an aside) that his measurement was an average up/down figure. That can only really mean that he has seen opposite forces in opposite orientations, at least one of which can't be buoyancy. Also, he has said he is seeing an immediate response and the RF pulse lasts one second, so for sure the frustrum isn't getting particularly hot on 63 Watts.
[That said, I think he very much needs to back up his statements with more data and details. He is talking about results much better than almost everyone, on a barely complete frustrum measured on a quickly assembled test rig. Like anyone with any sense I really want this effect to be true, but my credulity antennae are tingling a little over this report...]
R.
True, I just saw that. TT states:QuoteMeasured thrust from my 1st EmDrive experiment was 2.2mN (0.22g) @ 63Wf or 35mN/kW, averaged from small end up & down test setups.
If he actually means that in the orientation where the small end was facing up he read 2.3 mN per say, and then when he reversed orientation so that the small end was facing down he read -2.1 mN, and so the "average" thrust was calculated at 2.2 mN, I would be quite impressed. That would go along way to diminishing the possibility of any thermal effects as being the source of the reading.
When you say they are 1 second pulses, does that mean that during the 1 second interval in which the RF pulse is applied, the thrust rises from zero to the measured value and back again to zero as the interval ends, so that thrust and applied RF pulse are coincident in time? That would be something.
EDIT: Just for fun and to help get a conceptual handle on just how much 2.2 mN is, I weighed some household objects on a scale I have that is accurate down to 0.01 mg (0.1 uN).
A standard, yellow 3M post-it-note (see attached figure) weighs almost exactly 4.4 mN. So measured force at the moment is almost exactly half a post-it-note.
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Prof. Frobnicat, Paul March says that the EM Drive tests at NASA can be explained by Woodward's Mach Effect theory (as he calls it "the other side of the coin having Dr. White's Quantum Vacuum theory on the other side).
Prof. Woodward explains NASA's results as being due entirely to the asymmetric placement of the dielectric insert, constituting a Woodward Mach Effect, and that NASA's test without a dielectric giving no force confirms Prof. Woodward's expectations.
Now, this is how Prof. Woodward explains the Conservation of Energy (Overunity argument) for his theory (he wrote this last November 2015, barely a couple of months ago):
http://ssi.org/epi/Over-Unity_Argument_&_Mach_Effect_Thrusters.pdf
Your comments on Prof. Woodward's paper on Conservation of Energy, would be appreciated, and most relevant, because, again, Paul March at NASA has stated that Prof, Woodward's theory might explain the test results for the EM Drive at NASA.
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That interaction with the rest of the causally-connected universe is where the "extra" energy comes from. In fact it is the entire reason anything happens at all. The work done by an M-E thruster is largely unrelated to the local energy input, in the same sense in which the work done by the wind on a sailboat is largely unrelated to the energy expended by the crew moving the sails around. As far as I know there is no theoretical upper limit on the thrust efficiency of a Mach-effect device.
..
Ahh forgot, once the new RS485 100W Rf amp arrives, here is the new test setup as attached. Getting more KISS all the time. Means easier to replicate and verify the data.
. Your health is priority #1. We are concerned hearing that the EM Drive resonant cavity in the experiment is "held by gravity" and that it is not sealed, and apparently the resonant cavity is not inside a shielded box, but that there is just a shield plate between the EM Drive and the digital scale (if we read the sketch drawing correctly).
...
Edit - About a year ago, lots of back & forth about angles and Eagan's definitions: http://forum.nasaspaceflight.com/index.php?topic=36313.msg1323927#msg1323927
Not mine, ConeCalc. Try it for yourself and if its wrong, we need to advise I-Logic their software is faulty. I'm certain any company would need to know this. ..
Not mine, ConeCalc. Try it for yourself and if its wrong, we need to advise I-Logic their software is faulty. I'm certain any company would need to know this. ..
I tried it myself: http://www.i-logic.com/utilities/coneresult2.php3
There is nothing wrong with the ConeCalc calculations. They agree with mine. Again, they use a definition of the cone angle that is: 90 degrees - ConeHalfAngle
So, if you input into their software, the correct values (once one understands, from their drawing, what is their definition of angle)
BigDiameter=10.5
SmallDiameter=6.25
ConeAngle = 57 degrees (= 90 degrees - 33 degrees)
you get the same value for the height I calculated: 6.54/2 = 3.27
(see: https://forum.nasaspaceflight.com/index.php?topic=39004.msg1484429#msg1484429)
You have to input the correct values to get the correct output
...OK, got you height at a little over 3 inches, that does not correspond to any frustum I've seen.
, what part of the fact that 33 degrees is not my angle, it is the angle of Shawyer's superconducting fustrum of a cone is not clear ?


33 degrees was what I picked up from an earlier post with your name on it. I now understand this was a reference to Shawyers new superconductor cavity. So now I know of a 3 inch high frustum. Well, actually not since none of us have seen pics.

33 degrees was what I picked up from an earlier post with your name on it. I now understand this was a reference to Shawyers new superconductor cavity. So now I know of a 3 inch high frustum. Well, actually not since none of us have seen pics.Why would a 3.27 inch = 83 mm height frustum be ruled out? Why the shocking eyes?
Have you taken a look at what is the height of the frustum that Tajmar tested at TU Dresden in Germany, listing Shawyer as a consultant to his paper?
Answer = Tajmar's EM Drive height is listed as 68.6 mm = 2.70 inches
So, Tajmar's frustum, made with Shawyer as a consultant, had a reported height 21% smaller than 3.27 inches.
33 degrees was what I picked up from an earlier post with your name on it. I now understand this was a reference to Shawyers new superconductor cavity. So now I know of a 3 inch high frustum. Well, actually not since none of us have seen pics.Why would a 3.27 inch = 83 mm height frustum be ruled out? Why the shocking eyes?
Have you taken a look at what is the height of the frustum that Tajmar tested at TU Dresden in Germany, listing Shawyer as a consultant to his paper?
Answer = Tajmar's EM Drive height is listed as 68.6 mm = 2.70 inches
So, Tajmar's frustum, made with Shawyer as a consultant, had a reported height 21% smaller than 3.27 inches.Prof Tajmar's mini frustum was a big departure from the "conventional" 2.4 GHz ones floating about. I had shocking eyes then, just didn't post it.
All these different angles makes me wonder if there isn't a more systematical approach, instead of the trial and error method, which seems a rather arbitrary way of poking in the dark...
All these different angles makes me wonder if there isn't a more systematical approach, instead of the trial and error method, which seems a rather arbitrary way of poking in the dark...Agreed...which lead to my pontificating about angles and dimensions. Meep has been used for nasa sized frustums, not sure about new shawyer frustums. Actually, DIY types like myself are simply wanting to observe results without trying mini versions. I could be wrong, but don't think any DIY work is being done with shawyers smaller frustum except for possibly Univ of Dresden.

All these different angles makes me wonder if there isn't a more systematical approach, instead of the trial and error method, which seems a rather arbitrary way of poking in the dark...
...After the flawed inversion of sign in the CoE dealing annex of one of White cosigned papers, this paper by Woodward indicates that the leading theoreticians of propellantless propulsion are ready to ruin their reputation in the eyes of mindful readers with some decent bases in mechanics in return of keeping their distance with the "apparent free energy" taboo for the less vigilant followers (or backers ?)...
) free-energy aspect of the EM Drive, whether the peer-review editors have expertise in conservation of energy issues and whether the authors of EM Drive papers can adequately answer inquiries from peer-review editors on satisfactorily addressing the free-energy aspect of EM Drive theories.
) NSF user Dr. Notsosureofit is making (slow but) stronger advance in this area than the most prominently known authors in the field:EXACT SOLUTION OF TheTRAVELLER'S TEST GEOMETRY...
COMPARISON OF EXACT FREQUENCY with TheTraveller, for mode shape TE013
measured frequency: TheTraveller has not yet provided a measured natural frequency for his test
calculated natural frequency
(exact solution, Dr. Rodal using Wolfram Mathematica): 2.38793 GHz
calculated natural frequency
(by TheTraveller, using spreadsheet approximating cone as summation of cylinders): 2.4053 GHz
difference: (2.4053 - 2.38793)/2.4053 = 0.69 %
The exact solution is very close to the frequency calculated by TheTraveller approximating the cone as the sum of a large number of cylinders of constant cross-section, because the half cone angle of his frustum, being less than 10 degrees is pretty close to the geometry of a cylinder.
This difference of 0.69% in frequency is negligible, considering the fact that the TheTraveller's cone is presently "held by gravity" and is bound to have larger geometrical defects, which will affect the experimental natural frequency.
For reference, we also give the natural frequencies of the first four TE01p modes for TheTraveller's geometry:
TE011 = 1.77026*10^9 Hz
TE012 = 2.07472*10^9 Hz
TE013 = 2.38793*10^9 Hz
TE014 = 2.75007*10^9 Hz
...
