Plugged in some numbers to come up with the near field reactive and near field radiating using 2ghz and largest dimension of frustum 280mm.
Near field reactive: .024m
Near field radiating: .261m
But there is a problem with this near field scenario. This is for antennas. The frustum isn't an antenna. The outer surface is also grounded through the coax cable at a minimum. Thus this type of evanescent wave interaction is not an option.
References:
https://www.ic.gc.ca/eic/site/smt-gst.nsf/eng/sf10112.htmlhttp://en.wikipedia.org/wiki/Near_and_far_field#Near-field_characteristicsAnother possible method of evanescent wave production by TIRF is an option however, which is an optical phenomenon associated with boundary conditions of two different refractive indexes. I remain unconvinced that this applies to Emdrive solely because the air/copper/air boundary does not fit this scenario. Copper is a conductor, thus any evanescent E field component will completely vanish. Here's info from an expert over at Polywell:
http://www.talk-polywell.org/bb/viewtopic.php?f=10&t=2949&start=270#p118973Yes, evanescent waves are propagating waves. They propagate in the direction of the interface, so their momentum is parallel to the boundary. It is just their amplitude that decays exponentially away from the interface layer.
So in this context, evanescent waves "hug" the boundary. The propagate parallel to the boundary. They do not radiate away from the boundary. Their amplitude falls exponentially with distance, unlike radiating waves which fall off with inverse square. The above quote from Polywell matches any check of the literature online.
I am willing to play devil's advocate for a second and accept that evanescent waves do appear on the outer surface of the conical frustum.
Quoting the oracle,
http://en.wikipedia.org/wiki/Evanescent_wave They are formed at the boundary between two media with different wave motion properties, and are most intense within one third of a wavelength from the surface of formation.
The 1/3 wavelength figure also appears in other references. Evanescent fields would be most intense within .05m or ~2 inches from the conical frustum. Any structure within that range is subject to scrutiny.
We know, as was recent reported that this kind of evanescent wave can impart momentum and spin on particles in the following manner.
Momentum and spin represent fundamental dynamic properties of quantum particles and fields. In particular, propagating optical waves (photons) carry momentum and longitudinal spin determined by the wave vector and circular polarization, respectively. Here we show that exactly the opposite can be the case for evanescent optical waves. A single evanescent wave possesses a spin component, which is independent of the polarization and is orthogonal to the wave vector. Furthermore, such a wave carries a momentum component, which is determined by the circular polarization and is also orthogonal to the wave vector.
Thus for this type of evanescent wave to be applicable to Emdrive, there would have to be circularly polarized wave in use. The Emdrive is excited by linearly polarized plane waves. If it were excited by circularly polarized radiation, the momentum vector imparted on any particle nearby would be orthogonal to the direction of measured thrust. Under vacuum testing, these particles were removed. Thus this evanescent wave hypothesis does not hold.
http://www.nature.com/ncomms/2014/140306/ncomms4300/full/ncomms4300.htmlhttp://arxiv.org/ftp/arxiv/papers/1308/1308.0547.pdf
Now that I'm done playing devil's advocate, these are the only ways I can find in the literature to "tunnel" radiation out of a waveguide. You have to run it at cutoff and use metamaterials. None of these conditions fit Emdrive.
http://personal.us.es/marques/2005-PhysRevB_72_075116.pdfhttp://people.ee.duke.edu/~cummer/reprints/074_Liu08_PRL_EMTunnelingMeasurements.pdfA final method of producing evanescent waves is to operate the waveguide at or below cutoff. Given the .159 meter diameter of the small end, cutoff is 1886.79mhz. Any frequency lower than this would go evanescent inside the cavity. The lowest frequency in which a certain mode can propagate is the cutoff frequency of that mode. Evanescent modes are modes below the cutoff frequency. They cannot propagate down the waveguide for any distance, dying away exponentially. The only test that got close to cutoff was the TE012 test at 1880.4 from Brady et al, but this does not count as the frustum was loaded with PE, which displaced the E and H fields, changing the resonant frequency. So this does not count as running the device below cutoff, as it wouldn't resonate anyway if it were in cutoff.
Shawyer's statement, "The small end diameters are set just above the cut-off diameter corresponding to the mode and frequency of the design."
http://forum.nasaspaceflight.com/index.php?topic=29276.msg1275094#msg1275094Lastly it is well known from studying evanescent wave coupling and resonant inductive coupling that evanescent modes will NOT couple to another medium unless the other medium is resonant at that exact mode. So this mode of interaction is not a possibility.
http://en.wikipedia.org/wiki/Evanescent_wave#Evanescent-wave_couplinghttp://en.wikipedia.org/wiki/Resonant_inductive_couplinghttp://en.wikipedia.org/wiki/Wireless_powerI think this definitively puts evanescent wave theories to bed.