Yes and No as depend on the Launch azimuth and result inclination. That is one reason why Antares flights to ISS are going via Wallops. Higher Energy transfer to the 51.6 inclination on a descending node towards the equator results in more payload lifted for them than a 51.6 ascending node from CCAFS like shuttle and F9. [...]
Could you explain me why? I had it understood that the only advantage of latitude (assuming it is less than the orbit's inclination) is the Earth's rotation. Which is a vector with the exact direction of the rotation. Thus, the rocket needs to add the difference.
For example, let's say that orbital speed is 7,500m/s, and inclination is 51.6deg, then the (lat,long) component vector is (4,659m/s, 5,878m/s) for a northward orbit and (4,659m/s, -5,878m/s) of a southward on. So, launching southward or northward should be the same.
Due to the rotation of the Earth, your launch site supplies a (cos(lat)*radius m/s,0m/s) of energy. But you obviously then have to add atmospheric and gravity losses. Thus, if you execute no dogleg, launching from KSC (407m/s help) should actually give better performance than Wallops (365m/s). You'd get better performance from Wallops as you go orbits with higher inclinations than 87 deg or so, since you'd have to actually cancel the Earth rotation supplied by KSC.
But that's how I understand it, and that's clearly a simplistic model. Can you help me understand why southern azimuth give better performance, and also why closer latitude to orbit inclination gives better performance than closer to equator? I'm quite intrigued.