Quote from: vulture4 on 07/03/2012 04:13 amI would guess a lifting body is also unneeded BEO.More importantly, not possible from BEO. The reentry speeds and angles don't lend themselves to a gliding reentry. Unless you wanted to expend extra propellant needed to get yourself inserted back into a circularized LEO upon return from BEO, which is just plain silly. Better to design the spacecraft and TPS to take the heat of a ballistic reentry. And that's called a capsule.
I would guess a lifting body is also unneeded BEO.
Dreamchaser has a much lower lift to drag ratio than X-37C. The L/D of the X-37 is about 4.5, the DC is at about 3.5, too low for a safe landing without powered lift. Do you have citations or other data showing these L/D ratios? It is my impression that the DC lands un-powered as a glider?
Interesting. Faster than I would have guessed.
Quote from: vulture4 on 07/05/2012 04:13 pmInteresting. Faster than I would have guessed.The X-37C is stated to be 48 feet long as compared to the X-37B which is 29 feet long. The X-37B is about 11,000 lbsScaling Law:"When a physical object maintains the same density and is scaled up, its mass is increased by the cube of the multiplier "The ratio 48 to 29 feet is 1.65following the mass scaling law, the multiplier is 4.53,the scaled mass is 11,000 * 4.53 or almost 50,000lbs!The DC is roughly 30,000 lbs and lands somewhere between 190 and 200 knots. The caveat here is maintaining the same density, as I am not a aeronautical engineer (arm waving) I can't define this but I assume that the density will be lower on the X-37C when compared to the B model and the mass will be less than 50,000 lbs loaded.
Quote from: BrightLight on 07/05/2012 04:39 pmQuote from: vulture4 on 07/05/2012 04:13 pmInteresting. Faster than I would have guessed.The X-37C is stated to be 48 feet long as compared to the X-37B which is 29 feet long. The X-37B is about 11,000 lbsScaling Law:"When a physical object maintains the same density and is scaled up, its mass is increased by the cube of the multiplier "The ratio 48 to 29 feet is 1.65following the mass scaling law, the multiplier is 4.53,the scaled mass is 11,000 * 4.53 or almost 50,000lbs!The DC is roughly 30,000 lbs and lands somewhere between 190 and 200 knots. The caveat here is maintaining the same density, as I am not a aeronautical engineer (arm waving) I can't define this but I assume that the density will be lower on the X-37C when compared to the B model and the mass will be less than 50,000 lbs loaded.Need to keep in mind the X-37B is a "test" model.Your numbers are off.
Quote from: Prober on 07/06/2012 03:50 amQuote from: BrightLight on 07/05/2012 04:39 pmQuote from: vulture4 on 07/05/2012 04:13 pmInteresting. Faster than I would have guessed.The X-37C is stated to be 48 feet long as compared to the X-37B which is 29 feet long. The X-37B is about 11,000 lbsScaling Law:"When a physical object maintains the same density and is scaled up, its mass is increased by the cube of the multiplier "The ratio 48 to 29 feet is 1.65following the mass scaling law, the multiplier is 4.53,the scaled mass is 11,000 * 4.53 or almost 50,000lbs!The DC is roughly 30,000 lbs and lands somewhere between 190 and 200 knots. The caveat here is maintaining the same density, as I am not a aeronautical engineer (arm waving) I can't define this but I assume that the density will be lower on the X-37C when compared to the B model and the mass will be less than 50,000 lbs loaded.Need to keep in mind the X-37B is a "test" model.Your numbers are off.I realize that the X stands for experimental. The exercise was to demonstrate that it's not as simple to scale a spacecraft, what numbers are wrong? What is the mass of the x-37C? How does one scale a body?
The flaw in scaling is assuming a constant mass/volume ratio. In the case of Shuttle you would have a high M/V in the fore (cabin, RCS) and in the aft (engines, tanks). The center 60’ cargo bay would be relatively a low M/V and via a high percentage of overall dimension thus a source of error… Just for you to consider… Carry on
Quote from: Rocket Science on 07/06/2012 06:38 pmThe flaw in scaling is assuming a constant mass/volume ratio. In the case of Shuttle you would have a high M/V in the fore (cabin, RCS) and in the aft (engines, tanks). The center 60’ cargo bay would be relatively a low M/V and via a high percentage of overall dimension thus a source of error… Just for you to consider… Carry on I'm unclear as to whether the X-37 mass was with fuel. It seems to have a higher propellant mass fraction than the Shuttle Orbiter, though it's hard to tell what changes DOD made when they switched to hypergols. There is a Shuttle-like payload bay but it is relatively small.Here's a review of a presentation by Arthur Grantz of Boeing that has some detailed drawings of the proposed "C" model. Maybe they left the stern flat because they planned to put the APAS there.http://www.space.com/13230-secretive-37b-space-plane-future-astronauts.html