Quote from: Dalhousie on 03/02/2017 11:19 pmHow much power is needed to generate such a field?None, once established.
How much power is needed to generate such a field?
Quote from: Robotbeat on 03/02/2017 11:51 pmQuote from: Dalhousie on 03/02/2017 11:19 pmHow much power is needed to generate such a field?None, once established.The Earth's magnetic field is run by continuous energy release in the Earth's core. Why do you say this needs no power once it is set up?
Quote from: Dalhousie on 03/05/2017 10:15 pmQuote from: Robotbeat on 03/02/2017 11:51 pmQuote from: Dalhousie on 03/02/2017 11:19 pmHow much power is needed to generate such a field?None, once established.The Earth's magnetic field is run by continuous energy release in the Earth's core. Why do you say this needs no power once it is set up?Because you'd use superconductors, and superconductors don't have any measurable DC resistance. Or at least, I would use superconductors. I think they may be considering a different mechanism involving inflating the artificial magnetosphere with plasma, and that'd take power and mass.
Quote from: Robotbeat on 03/05/2017 10:22 pmQuote from: Dalhousie on 03/05/2017 10:15 pmQuote from: Robotbeat on 03/02/2017 11:51 pmQuote from: Dalhousie on 03/02/2017 11:19 pmHow much power is needed to generate such a field?None, once established.The Earth's magnetic field is run by continuous energy release in the Earth's core. Why do you say this needs no power once it is set up?Because you'd use superconductors, and superconductors don't have any measurable DC resistance. Or at least, I would use superconductors. I think they may be considering a different mechanism involving inflating the artificial magnetosphere with plasma, and that'd take power and mass.Those super conductors would need cooling. There would be energy losses through interaction with interplanetary fields. No free lunch. So, again, what power is required?
NO power required except for the initial 10^19 Joules to get the field established, at least if you just use superconducting coils.
No, it provides pressure on the magnetic field which compresses it, but does not reduce the current flowing in the magnets. You can't demagnetize an iron atom for the same reason.Yeah, the inflated artificial magnetosphere idea has gas loss mechanisms, though. But the superconducting coils do not lose strength.
I'm talking about enormous superconducting coils.
Just wrap the superconductor around the entire planet.Trying to build a magnetosphere by restarting the core is like trying to fly by flapping your arms and strapping wings on. Not only will you not possibly be able to put enough energy into the system to make it work, but there's a much easier method that ultimately is higher performing anyway (fixed wings and an engine).
Quote from: Robotbeat on 03/02/2017 11:51 pmQuote from: Dalhousie on 03/02/2017 11:19 pmHow much power is needed to generate such a field?None, once established.I don't know if that's true.It depends whether work is being done while deflecting the solar wind. If there is, then maintaining the magnetic field will require power.
Quote from: meekGee on 03/07/2017 07:04 amQuote from: Robotbeat on 03/02/2017 11:51 pmQuote from: Dalhousie on 03/02/2017 11:19 pmHow much power is needed to generate such a field?None, once established.I don't know if that's true.It depends whether work is being done while deflecting the solar wind. If there is, then maintaining the magnetic field will require power.No work is being done, just like a regular magnet. Unlike a regular magnet, you will not lose magnetism unless you get to a critical current or critical field value, which you won't in a properly engineered system.
The present paper reports the results of an extension of the theoretical study reported in references 1, 2, and 3 in which approximate results are determined for the traces, in the geomagnetic equatorial plane and in the geomagnetic meridian plane containing the sun-earth line, of the cavity carved out of a steady neutral ionized solar corpuscular stream by interaction with a magnetic dipole representing the geomagnetic field. The novel feature of this extension is the inclusion of the effect of an equatorial ring current having properties similar to those of the model proposed by Smith, Coleman, Judge, and Sonett in reference 4 to represent the magnetometer data from Pioneer V and Explorer VI. These properties are that there exists, during quiet times, a westward flowing current of about 5x10^6 amperes distributed over a large volume having the form of a toroidal ring 3 earth radii in cross-sectional radius with its center line situated in the geomagnetic equatorial plane at a distance of approximately 8 to 10 earth radii.
For no work to be done, no interaction / deflection must be done, thus no flux. So yes, you could have that situation, but in that case it wouldn't do anything, so why would you do it?..
Quote from: Space Ghost 1962 on 03/07/2017 08:37 pmFor no work to be done, no interaction / deflection must be done, thus no flux. So yes, you could have that situation, but in that case it wouldn't do anything, so why would you do it?..This is completely wrong.If I have an electric motor with permanent magnets, the magnets are obviously interacting. But they are not themselves doing work. The permanent magnets do not appreciably lose their magnetism, they last for the life of the vehicle.If I place an object on the hard floor and the object is sitting there, is the floor doing work? No. If I bounce a ball off the hard floor, is the floor doing work? Again, no. The floor does expend energy in order to deflect and interact with the ball. Same for a magnet.I can't believe we're having this discussion. Can someone else help me explain this really basic physical concept?