So if you were manufacturing hydrogen and oxygen by electrolysis of water (only) for an O2/H2 burning engine you would be short of hydrogen or would end up with excess oxygen? And related to this if you were making methane and oxygen using the sabatier reaction (oxygen and hydrogen from electroylsis of water and carbon dioxide as required) for a raptor engine you would similarly end up with an excess of oxygen?
Random question related to my pet peeve, suborbital refueling... Since the O/F ratio of kerolox and keroxide are 3 and 7 respectively... 100 tons of props should be- 87.5 mt H2O2 and 12.5 mt of kerosene - 75 mt and 25 mt of kerosene I was wondering if the second one would need to transfer fuel with oxidizer even with such a different O/F... the difference in mass is not that big, it is proportionally that the difference is large...