Neither Alice nor Bob know the "value" of their respective qubits. All they know is that the message that Alice transmits and the message that Bob sees on the qubits they have was pretty simple:...---...They still have no idea of the "value" of their respective qubits. The value is not necessary to decode the message. The message is not the medium, to coin a phrase.As Sanman asks, "In what crucial way does computation differ from communication?"
Quote from: sanman on 12/17/2023 07:26 amBut Ed, in quantum computing you do get to choose whether the bit is 1 or 0, because you're loading your information into the entangled qubits. You don't, because loading inputs bits into the computer and getting some answer bits out is how a classical computer works. It is not how a quantum computer works. Greatly simplified: you can arrange your Qbits into the representation of a function you want to compute, but observing those Qbits means you get one of the possible arrangements of bits that satisfies that function, whilst also 'breaking' your Qbits. If you want to get multiple results (i.e. to build up the probability distribution you were trying to find in the first place with your function) you re-create that function multiple times and get multiple answers. If that sounds weird and awkward and a terrible way to go about computation - yes it is, for classical computation. Quantum computers are absurdly worthless for performing the functions we are used to computer performing. That are exceptional only at performing functions that can be represented in the way quantum computation works, and are valuable for the edge cases where a function can both be expressed in a way that even makes sense to attempt quantum computation on, and that function also has some property that makes it unusually difficult to compute classically.
But Ed, in quantum computing you do get to choose whether the bit is 1 or 0, because you're loading your information into the entangled qubits.
user edzieba says:Quote from: edzieba on 12/18/2023 12:28 pmQuote from: sanman on 12/17/2023 07:26 amBut Ed, in quantum computing you do get to choose whether the bit is 1 or 0, because you're loading your information into the entangled qubits. You don't, because loading inputs bits into the computer and getting some answer bits out is how a classical computer works. It is not how a quantum computer works. Greatly simplified: you can arrange your Qbits into the representation of a function you want to compute, but observing those Qbits means you get one of the possible arrangements of bits that satisfies that function, whilst also 'breaking' your Qbits. If you want to get multiple results (i.e. to build up the probability distribution you were trying to find in the first place with your function) you re-create that function multiple times and get multiple answers. If that sounds weird and awkward and a terrible way to go about computation - yes it is, for classical computation. Quantum computers are absurdly worthless for performing the functions we are used to computer performing. That are exceptional only at performing functions that can be represented in the way quantum computation works, and are valuable for the edge cases where a function can both be expressed in a way that even makes sense to attempt quantum computation on, and that function also has some property that makes it unusually difficult to compute classically.But if we can jig this up for computation, then why can't we do so for communication as well?It seems to me that computation is like communication, but with extra stuff added on (ie. communication is a pre-requisite for computation. if you can do computation, you can do communication)Using your example above, if our qubits are entangled to form a function, but we already know the answers to that function, then given enough samples (ie. enough entangled setups) then shouldn't we be able to deduce which particular qubit was measured and messed up the entanglement? Because by measuring enough samples (ie. entangled qubit functions) we can tell what's consistently matching the function value it's supposed to have, versus what's looking random and no longer entangled. So isn't that a way to encode a signal?
Because you're still not transmitting any information that way. You're both able to conclude that 1+1=2 (or whatever your function is) but you don't get to choose the inputs. Even if you can deduce the inputs from the outputs, you then just have knowledge of what those unchooseable inputs were at both ends: in exactly the same position as just straight-up measuring the entangled pairs directly. New Physics would be the appropriate place for this thread, as transmitting information superluminally via entanglement is not consistent with either Relativistic physics or QM.
Here's a spaceflight scenario that uses quantum communication to get everyone to the correct rendezvous.Suppose we make a spaceship that can go to Alpha Centauri, a triple start system in 10 years per light year, or Proxima Centauri in 43 years. (Proxima, Centauri A, Centauri B).Supposes when they get to Proxima (the first star), they have a choice of which start to go to next, either Centauri A or Centauri B. They can flip a coin, doesn't matter which.Now, before they left Earth, they entangled some quantum bits and one bit is on Earth.Now, Earth needs to know which wait to aim its interstellar capable tight beam radio or laser. So they know to aim it a Proxima at the start.Now, when spaceship at Proxima rolls the dice, they do so by measuring the entangled quantum bit. If it points up, they go to Centauri A. If it points down, they go to Centauri B.Earth instantly knows which way to aim the antenna, without a round trip message from Proxima saying "We are going to X". They just look at their version of the bit, and point the antenna using inverted logic that the spaceship is using.Now, the same thing applies if that spaceship decides to head to one of two other different star systems, and Earth wants to send a spaceship to rendezvous.Now this is kind of silly, because they could have planned the route in advance, using a coin instead of a quantum bit.But it's not silly if there's a war involved, because making random choices at the last second helps confuse the enemy and prevents spies at the origin of the spacecraft from leaking the predetermined choice. The enemy is now forced to spread its defenses between Centauri A and Centauri B in the above example, and can't use spies to concentrate its forces.What I described is no different than quantum encryption. The spy/snooper can't see the random number that the communicating parties can instantly share.What it doesn't get you is any useful information. If our spaceship arrives at Proxima and spies a nice planet in the Goldilocks zone of Centauri A (or a concentration of forces), it can't tell Earth about it instantly, its going to take 4.3 years to tell Earth.
Great story. So the moral of your story is that when we can accept or actually want randomness, then quantum entanglement can keep us in the know. As a variant on your story, if we wanted to distribute space mines across some region of space in a random pattern, we could use quantum entanglement to decide the distribution, and still secretly know where all the mines were.
Rendezvous is an old problem of assuring that two or more parties, initially separated, not knowing the position of each other, and not allowed to communicate, are striving to meet without pre-agreement on the meeting point. This problem has been extensively studied in classical computer science and has vivid importance to modern and future applications. Quantum non-locality, like Bell inequality violation, has shown that in many cases quantum entanglement allows for improved coordination of two, or more, separated parties compared to classical sources. The non-signaling correlations in many cases even strengthened such phenomena. In this work, we analyze, how Bell non-locality can be used by asymmetric location-aware agents trying to rendezvous on a finite network with a limited number of steps. We provide the optimal solution to this problem for both agents using quantum resources, and agents with only 'classical' computing power. Our results show that for cubic graphs and cycles it is possible to gain an advantage by allowing the agents to use the assistance of entangled quantum states.
I like it! Quantum mine deployment, or Ansible Mine Deployment. The "secretly know" could be warships light years away and adjust course accordingly, which is far cheaper in energy (the farther away, the cheaper it is to change course, triangles being what they are).Would make a great plot device for a military sci-fi. I'm pretty sure it is plausible.
One might posit that QE allows one party to create a random leg of a triangle which starts at their location and another party at a distance to follow the hypotenuse (shortest path) of that triangle.
Here's the TL;DR version of QE:tired: God doesn't play dicewired: It doesn't matter where you play entangled dice
ArticlePublished: 29 June 2023Quantum Advantage in Microwave Quantum RadarR. Assouly, R. Dassonneville, T. Peronnin, A. Bienfait & B. Huard Nature Physics volume 19, pages1418–1422 (2023)Cite this articleAbstractA central goal of any quantum technology consists in demonstrating an advantage in their performance compared to the best possible classical implementation. A quantum radar improves the detection of a target placed in a noisy environment by exploiting quantum correlations between two modes, probe and idler. The predicted quantum enhancement is not only less sensitive to loss than most quantum metrological applications, but it is also supposed to improve with additional noise. Here we demonstrate a superconducting circuit implementing a microwave quantum radar that can provide more than 20% better performance than any possible classical radar. The scheme involves joint measurement of entangled probe and idler microwave photon states after the probe has been reflected from the target and mixed with thermal noise. By storing the idler state in a resonator, we mitigate the detrimental impact of idler loss on the quantum advantage. Measuring the quantum advantage over a wide range of parameters, we find that the purity of the initial probe-idler entangled state is the main limiting factor and needs to be considered in any practical application.
Great story. So the moral of your story is that when we can accept or actually want randomness, then quantum entanglement can keep us in the know. As a variant on your story, if we wanted to distribute space mines across some region of space in a random pattern, we could use quantum entanglement to decide the distribution, and still secretly know where all the mines were.So quantum entanglement can be used to let the qubit(s) communicate to us and dictate our choices/information, even if we can't use entanglement to communicate to each other.
If the weak measurement thing was possible, then how would that change things?
You're not actually communicating anything there, either. What you are instead doing is effectively distributing a one-time-pad in a manner that can be proven to not have been intercepted before you read it. That's the basis of Quantum Crypt ography: not being 'more secure' than other crypt ographic methods (because the actual data is encrypted classically), but instead providing a guarantee that your key has not been intercepted in transit.
Quote from: edzieba on 12/22/2023 12:56 pmYou're not actually communicating anything there, either. What you are instead doing is effectively distributing a one-time-pad in a manner that can be proven to not have been intercepted before you read it. That's the basis of Quantum Crypt ography: not being 'more secure' than other crypt ographic methods (because the actual data is encrypted classically), but instead providing a guarantee that your key has not been intercepted in transit. Well, if some information being communicated is not of your own choosing, then isn't it still communication?
No, it's not. To both parties it's indistinguishable from a perfect random number generator.Worse yet, you can't "ring" the other device. Neither party even knows when or if the other party has actually tried to communicate any information or not. In fact it's meaningless to even ask the question, because the question assumes some system of absolute (or even merely self-consistent) simultaneity, which violates SR.
Quote from: Twark_Main on 12/22/2023 10:07 pmNo, it's not. To both parties it's indistinguishable from a perfect random number generator.Worse yet, you can't "ring" the other device. Neither party even knows when or if the other party has actually tried to communicate any information or not. In fact it's meaningless to even ask the question, because the question assumes some system of absolute (or even merely self-consistent) simultaneity, which violates SR.So you feel there's no "spooky action at a distance"
- it's all as if someone first deposited similar/related information into 2 envelopes, and then sent them to separate destinations to be opened/discovered later.
Can you explain how the "bomb experiment" works without "spooky" weirdness?
In past debates, people always reply "Yes, but you need to compare notes by classical methods to know a signal was passed."
Worse yet, you can't "ring" the other device. Neither party even knows when or if the other party has actually tried to communicate any information or not. In fact it's meaningless to even ask the question, because the question assumes some system of absolute (or even merely self-consistent) simultaneity, which violates SR.
Quote from: sanman on 12/21/2023 01:32 amIn past debates, people always reply "Yes, but you need to compare notes by classical methods to know a signal was passed." Asking if a single particle is in an entangled state is akin to asking if a single particle is "faster".
One is not measuring a relative variable like "faster", either. For example electron spin is a binary 1 or 0 (-1/2 or +1/2). If one of two entangled electrons is +1/2, the other is going to be -1/2
Yes, that's what I was referring to when I mentioned prior knowledge. But this doesn't help us, because the converse is also true. Which is to say, you cannot know, by only measuring that single particle, when the particle instead loses its entangled state. Quote from: InterestedEngineer on 12/22/2023 11:55 pmOne is not measuring a relative variable like "faster", either. For example electron spin is a binary 1 or 0 (-1/2 or +1/2). If one of two entangled electrons is +1/2, the other is going to be -1/2Actually, yes, that's a relative measurement. The reason is that you're not measuring the magnitude of spin, but rather the orientation, and that's actually an arbitrary choice. It's usually phrased/chosen as spin up and spin down, but you could just as easilly choose spin left and spin right as your basis. What Bells experiment actually did was deliberatley alter the basis of choice and track how the results correlated. If your choice of spin up/down is, say, 20 degrees off from my choice of spin up/down, interesting things happen. But you need to know exactly what I measured for it to have any significance.