Re number 2) HEEO-based refuelling: I think specifically, the conops where you fill up LSS in vLEO, then top it up during a single orbit in vLEO+1600-2000 m/s with a buddy tanker, rendezvousing shortly after the first burn - seems to me the most obvious way to handle that case, and as good a reason as any to set a lower limit on how slowly the system will pump propellant. In that case you would need to transfer 500-600t of prop during a 3-4 hour orbit (~50kg/s). So presumably the pump power can be less than 1kW, but not by very much.
Quote from: mikelepage on 02/03/2023 07:31 amRe number 2) HEEO-based refuelling: I think specifically, the conops where you fill up LSS in vLEO, then top it up during a single orbit in vLEO+1600-2000 m/s with a buddy tanker, rendezvousing shortly after the first burn - seems to me the most obvious way to handle that case, and as good a reason as any to set a lower limit on how slowly the system will pump propellant. In that case you would need to transfer 500-600t of prop during a 3-4 hour orbit (~50kg/s). So presumably the pump power can be less than 1kW, but not by very much.VLEO+2000 is about a 5.5 hour orbit. Being able to do RPOD, pre-transfer checkout, post-transfer prep, undocking/prox ops, and pre-insertion checkout in 2.5 hours seems pretty optimistic.
Random thought from another thread:It seems reasonable always to point a depot's nose at the Sun. That way, the ogive portion of the nose can act as a dewar for the LCH4 tank below it, and very little incident radiation should strike the LCH4 or LOX tank walls. (The Sun has an angular diameter of 0.53º, so the total incident flux should be sin (0.53º/2) = 0.0046 * solarConstant = 6.3W/m², which is almost nothing.)However, that leaves the albedo radiation reflected/emitted from Earth. I believe the average flux at mid-latitude inclinations is about 250W/m².Let's divide the sphere that the depot sees into three sections:1) The Sun. Dealt with via pointing at it.2) The sunlit or nighttime Earth. 250W/m², over some variable viewing angle.3) Empty space, which is presumably cold.Inside the depot's tanks, we will have:a) Conductive heating when a blob of prop touches a hot tank wall. Tank walls should only be truly hot if they're facing the sunlit Earth.b) Conductive/convective heating, where the ullage gas picks up heat from a tank wall and transmits it thermally to a blob of liquid prop.c) Radiative heating, where a hot wall emits IR directly into a blob of prop (bad), or some other section of wall (considerably less bad).Radiative heating ought to be fairly modest, because any particular spot on a tank wall ought to cycle between fairly hot while directly heated by Earth and cooling when pointed at the Earth nightside or at empty space. flux = εσT⁴, so even modest declines in the temperature of the inside wall result in much less radiative heating.So what if we apply continuous, extremely low acceleration toward the Earth? That should put whatever prop is in the depot as far away from a hot wall as possible, minimizing conductive heating. This won't help much if the depot is mostly full, but before it's more than half full, this should dramatically reduce heat transfer.Does this make sense?Note that continuous radial acceleration in a circular orbit doesn't actually change the shape of your orbit. It just makes you go around faster, making your true anomaly larger than it would be if you were in freefall. So the navigational consequences of this are easy to work around.This also requires pretty fancy RCS management to achieve, since we're holding the attitude of the depot fixed by pointing it at the Sun. Seems like a reasonable problem, though. Also, I'd think that whatever boiloff does occur should be able to power cold gas thrusters, both for the radial ullage burn and the burns necessary to counteract Earth's tidal forces, which want the nose to point at the center of the Earth, rather than at the Sun.
It seems reasonable always to point a depot's nose at the Sun.
Good and interesting hypothesis. Now do the math.There's also a heat shield that can be pointed at the Earth, so the Earth is only heating the tail and the heat shield. The tiles should absorb all that heat and release it right back at the Earth, and the insulation will keep the stainless steel cool on that side.
Quote from: TheRadicalModerate on 02/23/2023 08:52 pmIt seems reasonable always to point a depot's nose at the Sun. Is it, though? As we've discussed upthread, if it is far away from Earth or the moon, a depot coated in Solar White tiles will get cold enough to freeze oxygen (or close to it), even though it's otherwise unshielded from the direct sun. What messes this up in LEO is the warmth from the Earth, which comes at inconvenient wavelengths.
In that case, why not make the depot long and thin and keep it pointed at the Earth, not the sun? In that case, if you want some small amount of microgravity, hang a counterweight on a long cable from the nose of the depot in the direction of the Earth. (I haven't figured out how much mass/cable you'd need to get, say, 50 micro-g; it seems to involve solving a cubic, and I'm too sleepy at the moment . . .)
Quote from: TheRadicalModerate on 02/23/2023 08:52 pmIt seems reasonable always to point a depot's nose at the Sun. Is it, though? As we've discussed upthread, if it is far away from Earth or the moon, a depot coated in Solar White tiles will get cold enough to freeze oxygen (or close to it), even though it's otherwise unshielded from the direct sun.
Problem is you can't "point" toward the Earth as it's nearly half the sky in LEO. So...
Quote from: Greg Hullender on 02/24/2023 01:14 amQuote from: TheRadicalModerate on 02/23/2023 08:52 pmIt seems reasonable always to point a depot's nose at the Sun. Is it, though? As we've discussed upthread, if it is far away from Earth or the moon, a depot coated in Solar White tiles will get cold enough to freeze oxygen (or close to it), even though it's otherwise unshielded from the direct sun. Vera Rubin is going to love that....One good approach is to keep the nose slightly "nose up" with respect to the Sun. Some additional insolation falls on the insulated tiles, but it's worth it to shade the uninsulated stainless backside.Quote from: Robotbeat on 02/24/2023 03:23 amProblem is you can't "point" toward the Earth as it's nearly half the sky in LEO. So...You can do a pretty good job, regardless.When the Sun is at a low angle, you point the black tiles at the Earth.As the Sun climbs higher (and your nose pitches up to track it), you roll, keeping the black tiles aimed at the more sunlit half of the Earth—rolling clockwise when the the Sun is on the left side of the sky, anti-clock when it's on the right.This attitude minimizes both thermal/albedo heating from Earth and nuisance reflections, because the brightest/warmest part of the Earth is seeing the black insulated tiles.After half an orbit the Sun is now "behind" you, and the vehicle has rolled 180°, so the black tiles are again pointing at the Earth. The nose remains pointed at the Sun.CMGs are great here. The ISS CMG would be more than sufficient, and (with decades-old technology) it masses about 1 metric ton.You can use the same CMG during the trip to Mars. During a solar storm the main radiation direction "wiggles around" a lot, and if you can continuously align the vehicle in that direction you get improved radiation protection for the same mass. The motion is not fast (<0.1 °/s), so it shouldn't cause discomfort.
The ISS has four, so figure four tons.
Ahh, but ISS masses 419t, and SS depot variant clocks on at 85t (dry) + 1600t propellant + 20t (guesstimate for cryo cooling, shades, PV and a hefty battery pack). Call it 1705t. Have I slipped a decimal somewhere? A loaded SS depot is 4x the mass of the ISS?
Quote from: OTV Booster on 02/26/2023 02:07 amThe ISS has four, so figure four tons.Each CMG is 600 lbs (of that, the spinning mass itself is 220 lb). Accounting for sig figs, that's a total system mass of 1.0-1.2 metric tons.Quote from: OTV Booster on 02/26/2023 02:07 am Ahh, but ISS masses 419t, and SS depot variant clocks on at 85t (dry) + 1600t propellant + 20t (guesstimate for cryo cooling, shades, PV and a hefty battery pack). Call it 1705t. Have I slipped a decimal somewhere? A loaded SS depot is 4x the mass of the ISS?Angular momentum is what really matters, not mass. That's a product of the moment of inertia and the maximum rate of rotation.The ISS is over 100 meters long, so it has a large angular momentum per mass. For Starship most of the mass is concentrated in the tanks, so it's nice and compact for a low moment of inertia.A depot is all tanks, of course, but it's still half as long (you said ~1700 tonnes so no stretch tanker). The way moment of inertia scales, that means ~1/4 the moment of inertia per mass.
Can you use a CMG in a system with a center of mass that changes radically?
Quote from: TheRadicalModerate on 02/26/2023 08:52 pmCan you use a CMG in a system with a center of mass that changes radically?Three words: ISS construction sequence.
Quote from: OTV Booster on 02/26/2023 02:07 amThe ISS has four, so figure four tons.Each CMG is 600 lbs (of that, the spinning mass itself is 220 lb). Accounting for sig figs, that's a total system mass of 1.0-1.2 metric tons.Quote from: OTV Booster on 02/26/2023 02:07 am Ahh, but ISS masses 419t, and SS depot variant clocks on at 85t (dry) + 1600t propellant + 20t (guesstimate for cryo cooling, shades, PV and a hefty battery pack). Call it 1705t. Have I slipped a decimal somewhere? A loaded SS depot is 4x the mass of the ISS?Angular momentum is what really matters, not mass. That's a product of the moment of inertia and the maximum rate of rotation.The ISS is over 100 meters long, so it has a large moment of inertia per mass. For Starship most of the mass is concentrated in the tanks, so it's nice and compact.A depot is all tanks, of course, but it's still half as long (you said ~1700 tonnes so no stretch tanker). The way moment of inertia scales, that means ~1/4 the moment of inertia per mass.And of course we're rolling the Starship, which is the axis with the lowest moment of inertia.
Quote from: Twark_Main on 02/26/2023 08:35 pmQuote from: OTV Booster on 02/26/2023 02:07 amThe ISS has four, so figure four tons.Each CMG is 600 lbs (of that, the spinning mass itself is 220 lb). Accounting for sig figs, that's a total system mass of 1.0-1.2 metric tons.Quote from: OTV Booster on 02/26/2023 02:07 am Ahh, but ISS masses 419t, and SS depot variant clocks on at 85t (dry) + 1600t propellant + 20t (guesstimate for cryo cooling, shades, PV and a hefty battery pack). Call it 1705t. Have I slipped a decimal somewhere? A loaded SS depot is 4x the mass of the ISS?Angular momentum is what really matters, not mass. That's a product of the moment of inertia and the maximum rate of rotation.The ISS is over 100 meters long, so it has a large angular momentum per mass. For Starship most of the mass is concentrated in the tanks, so it's nice and compact for a low moment of inertia.A depot is all tanks, of course, but it's still half as long (you said ~1700 tonnes so no stretch tanker). The way moment of inertia scales, that means ~1/4 the moment of inertia per mass.Can you use a CMG in a system with a center of mass that changes radically? There's a pretty big difference between an empty depot and a full one.
While writing the two posts above it struck me that if the depot and other ship are physically tightly bound the control systems had also better be tightly bound.Would it be best if the Depot completely took over and controlled both ships? Every cooperative arrangement that I come up with for settling thrust and attitude control seems to get more complicated the deeper I get into it. The last thing we want is the two ships fighting each other because of minor calibration issues.