On the subject of potential peaceful applications of nuclear explosives for space exploration (other than as spacecraft propulsion), would it possible to use several precisely delivered nuclear explosive charges to "safely (in a highly elastic sense)" bring a sub-kilometer asteroid to Earth surface, for scientific and/or commercial mineral extraction purposes? While there are plenty of discussions about using nuclear explosives for near Earth object (NEO) impact avoidance, not much is said about using similar methods to intentionally bring asteroids on collision course with Earth for scientific or commercial purposes.
Any asteroid can fall on the Sun, and it's free.
I don't know how to do calculations of the three-body problem, but here's a creative solution, please criticize. Any asteroid can fall on the Sun, and it's free. Let's drop a massive bouncer on an asteroid. He jumps elastically in the gravitational field of the asteroid, but against the orbital motion of the asteroid. And every fall, the impact of the bouncer into the asteroid greatly slows down the asteroid and it falls into the Sun.There is a simple magic here, where the force of gravity of the sun slows down the bouncer during an elastic rebound. This creates an asymmetry in the exchange of impulses of the bouncer and the asteroid in favor of the attraction of the Sun. And the asteroid falls on the Sun and approaches the Earth.
Quote from: Alex_O on 05/25/2022 09:05 pmAny asteroid can fall on the Sun, and it's free.No, de-orbiting to impact the sun takes an enormous amount of delta-V. The rest of the post is even less correct.
Quote from: Alex_O on 05/25/2022 09:05 pmI don't know how to do calculations of the three-body problem, but here's a creative solution, please criticize. Any asteroid can fall on the Sun, and it's free. Let's drop a massive bouncer on an asteroid. He jumps elastically in the gravitational field of the asteroid, but against the orbital motion of the asteroid. And every fall, the impact of the bouncer into the asteroid greatly slows down the asteroid and it falls into the Sun.There is a simple magic here, where the force of gravity of the sun slows down the bouncer during an elastic rebound. This creates an asymmetry in the exchange of impulses of the bouncer and the asteroid in favor of the attraction of the Sun. And the asteroid falls on the Sun and approaches the Earth.Your idea is a bit vague but seems to violate the conservation of angular momentum of the bouncer/asteroid/sun system.
1. Introduction. Attraction of a body of finite dimensionsUsually there is no need to remember that a satellite flying in orbit around the Earth is a body, not a material point. When calculating orbits about this,usually don't remember. But the fact remains: the force of gravity of the Earth acting on a body differs from the force acting on a material point of the same mass as the body, located at the same distance from the center of the Earth as the center of mass of the body. Amazing conclusions can follow from this obvious, but easily forgotten fact!
2 Pulsating SpaceshipOur reasoning boils down to three points:1) The gravitational force acting on a body of finite dimensions,different from the force acting on a material point of the same mass,concentrated at the center of mass of the body.2) By changing the size and shape of the body, you can change the valuethe gravitational force acting on it.3) These changes in the size and shape of the body can be controlled in such a way that the resulting variations in the force of gravity over time will lead to a significant difference in the trajectory of the body from the original.The first of these statements is obvious. The second is a consequence of the first. The third assertion will be proved below.
As a result of the described process, the energy spent on “turning on” and “off” the dumbbell is pumped into the energy of movement.apparatus in orbit, which allows you to disperse the apparatus up to the departure from the Earth's gravitational field. The orbit of the apparatus represents in this case an unwinding spiral with a number of turns equal to the number of dumbbell pulsations. A spacecraft whose orbit changes due to variations in the gravitational force acting on the craft is called a gravitational plane.The internal forces expended on “turning on” and “off” the dumbbell give a noticeable external effect because (and only because) an external force field exists and interacts. This requires a certain resonant tuning between the external and internalforces.
Alex_O: 1. The asteroid is in an orbit around the Sun. Let's assume that it is a circular orbit, to make this easy. The only way to bring it closer to the Sun is to reduce it's velocity in that orbit. Do that however you want, but understand that a huge amount of energy is required to make a significant change to the orbital velocity of the huge mass of that asteroid.2. Now the asteroid is in a new orbit, an elliptical orbit. The high point of that orbit is at the same distance from the Sun. On the other side of the Sun is the low point of the new orbit.That's all there is. No magic.Your "jumper" idea does nothing. Even if your "jumper" mass is on the opposite side of the asteroid to the Sun, it can't get a magical gain in force, because it is under the same influence from the Sun as the asteroid throughout the process, not just on the way down. There is no gain.
Quote from: darkenfast on 05/26/2022 04:53 amAlex_O: 1. The asteroid is in an orbit around the Sun. Let's assume that it is a circular orbit, to make this easy. The only way to bring it closer to the Sun is to reduce it's velocity in that orbit. Do that however you want, but understand that a huge amount of energy is required to make a significant change to the orbital velocity of the huge mass of that asteroid.2. Now the asteroid is in a new orbit, an elliptical orbit. The high point of that orbit is at the same distance from the Sun. On the other side of the Sun is the low point of the new orbit.That's all there is. No magic.Your "jumper" idea does nothing. Even if your "jumper" mass is on the opposite side of the asteroid to the Sun, it can't get a magical gain in force, because it is under the same influence from the Sun as the asteroid throughout the process, not just on the way down. There is no gain.I thought that the jumper gives the first jump along the vector against the rotation of the astroid around the Sun. It takes off to a height of 10 km (slowly) (due to the energy of the explosion of a large nuclear bomb) and falls back due to the gravity of the asteroid. And returns the energy of the explosion back to the asteroid for reuse (energy recovery).The magic is that the asteroid flies along the slope of a large gravitational pit (funnel), which is created by the gravity of the Sun. And after the first jump, the asteroid deorbits and falls deep into the gravitational hole.(the hippo fell into the swamp).Yes, the jumper tries to drag the asteroid behind him (accelerate) by the force of his gravity, at the moment of his flight over the asteroid. But this will be work not only against the force of gravity (inertia) of the asteroid, but also against the powerful force of attraction of the asteroid by the Sun. And it seems that a very useful asymmetry arises here, which will eventually drop the asteroid on the Sun.Yes, these are small forces, but if the jumper is very elastic, then the jumper will be able to make (conditionally) a million (billion) jumps due to the call of just one nuclear bomb, and we see that the useful result (logistics) already depends on the frequency!!! This is a very beautiful idea - when everything depends on the frequency.
Quote from: Alex_O on 05/26/2022 08:06 amQuote from: darkenfast on 05/26/2022 04:53 amAlex_O: 1. The asteroid is in an orbit around the Sun. Let's assume that it is a circular orbit, to make this easy. The only way to bring it closer to the Sun is to reduce it's velocity in that orbit. Do that however you want, but understand that a huge amount of energy is required to make a significant change to the orbital velocity of the huge mass of that asteroid.2. Now the asteroid is in a new orbit, an elliptical orbit. The high point of that orbit is at the same distance from the Sun. On the other side of the Sun is the low point of the new orbit.That's all there is. No magic.Your "jumper" idea does nothing. Even if your "jumper" mass is on the opposite side of the asteroid to the Sun, it can't get a magical gain in force, because it is under the same influence from the Sun as the asteroid throughout the process, not just on the way down. There is no gain.I thought that the jumper gives the first jump along the vector against the rotation of the astroid around the Sun. It takes off to a height of 10 km (slowly) (due to the energy of the explosion of a large nuclear bomb) and falls back due to the gravity of the asteroid. And returns the energy of the explosion back to the asteroid for reuse (energy recovery).The magic is that the asteroid flies along the slope of a large gravitational pit (funnel), which is created by the gravity of the Sun. And after the first jump, the asteroid deorbits and falls deep into the gravitational hole.(the hippo fell into the swamp).Yes, the jumper tries to drag the asteroid behind him (accelerate) by the force of his gravity, at the moment of his flight over the asteroid. But this will be work not only against the force of gravity (inertia) of the asteroid, but also against the powerful force of attraction of the asteroid by the Sun. And it seems that a very useful asymmetry arises here, which will eventually drop the asteroid on the Sun.Yes, these are small forces, but if the jumper is very elastic, then the jumper will be able to make (conditionally) a million (billion) jumps due to the call of just one nuclear bomb, and we see that the useful result (logistics) already depends on the frequency!!! This is a very beautiful idea - when everything depends on the frequency.If I understand what you are saying then each jump will slow the asteroid for a bit but then as gravity drags the jumper to a stop the asteroid will speed up again. As gravity pulls the jumper down the asteroid will speed up even more. As the jumper impacts the asteroid it slows down to its original speed. If the jumper bounces then the asteroid will slow again.Each fall will exactly cancel the effect of each jump in a cycle. This is conservation of momentum.
You cannot generate any more energy than that imparted by the one explosion, especially if your jumper is a chunk of rock blasted off the asteroid. The rock cannot generate energy out of nothing. It will either escape the asteroid and go into it's own orbit around the Sun (while the original asteroid has it's orbit changed as well), OR if it's velocity is not enough to escape, then it will fall back to the asteroid. It doesn't matter how many times you bounce, or what sort of "elastic" your jumper has. Both the asteroid and the jumper feel the attraction of the Sun. That attraction is defined by the mass of the Sun. It's what keeps the asteroid in its free-fall orbit around it.What you are talking about is like expecting a bowling ball, thrown up from a trampoline, to keep bouncing higher and higher without any additional energy being added. Edit to add: This was in reply to Alex_O.
Alex_O, your proposal has the exact same issues as the last several oscillating-mass schemes you've posted threads on. You can consult the previous threads you've made for resources people have posted to read in order to learn about how Newtonian mechanics work.
Quote from: edzieba on 05/26/2022 12:02 pmAlex_O, your proposal has the exact same issues as the last several oscillating-mass schemes you've posted threads on. You can consult the previous threads you've made for resources people have posted to read in order to learn about how Newtonian mechanics work.Alex_O: Please, please, please learn about conservation of momentum. It is at the very heart of space science. https://en.wikipedia.org/wiki/MomentumPlease refrain from posting on subjects relating to change of orbits until you have assimilated this concept, because you are just embarrassing yourself. Basically, unless an outside force acts on a system, then some of the system's mass must leave the system to change the momentum of the rest of the system.