Quote from: Star One on 08/06/2015 12:09 pmIndeed interesting article. It seems as if the EM drive is now getting a marginally better response in articles like this. Unfortunately it will probably see years of so called wars until a conclusion appears one way or the other.Even if someone makes a EM Drive and flies it up the tailpipes of other theories it will be controversial, it will take years to settle down. Nature of the beast.Shell
Indeed interesting article. It seems as if the EM drive is now getting a marginally better response in articles like this. Unfortunately it will probably see years of so called wars until a conclusion appears one way or the other.
Nice work.Clearly explains why EMDrive generated Force scales with Q and why a high Q EMDrive can deliver much more Force than can a photon rocket.In an EMDrive ....... Q Rules
Quote from: meberbs on 08/06/2015 06:13 amv2/v1 = sqrt(a^2 + 4*a +1)-a-1, where a=m*c^2/(h*v1)where v2 is the new frequency, v1 is the starting frequency, m is the mass of the mirror that the photon reflects off, h and c are the usual constants.The formula is fine when a=0, because then v2/v1=0 as expected.But when a >1 (the macroscopic case we have here), v2/v1 >1 also, which seems to make no sense.
v2/v1 = sqrt(a^2 + 4*a +1)-a-1, where a=m*c^2/(h*v1)where v2 is the new frequency, v1 is the starting frequency, m is the mass of the mirror that the photon reflects off, h and c are the usual constants.
Old sailors trick.Use 0.25m long pieces of old cassette tape. Very low mass but high surface area.What I expect to see is air being thrown outward from the rotating table and being drawn up from the floor and down from the roof to make up for the air being thrown outward.
Quote from: TheTraveller on 08/06/2015 07:28 amNice work.Clearly explains why EMDrive generated Force scales with Q and why a high Q EMDrive can deliver much more Force than can a photon rocket.In an EMDrive ....... Q RulesNote that most of the post was referring to an open system where only one mirror is attached to the vehicle. If this explains EM drive thrust, the Q factor that matters would be between the device and the chamber walls. Still, assuming there is some new physics behind the EM drive, similar calculations would probably apply.Quote from: deltaMass on 08/06/2015 08:11 amQuote from: meberbs on 08/06/2015 06:13 amv2/v1 = sqrt(a^2 + 4*a +1)-a-1, where a=m*c^2/(h*v1)where v2 is the new frequency, v1 is the starting frequency, m is the mass of the mirror that the photon reflects off, h and c are the usual constants.The formula is fine when a=0, because then v2/v1=0 as expected.But when a >1 (the macroscopic case we have here), v2/v1 >1 also, which seems to make no sense.I think you are filling in some numbers wrong. v2/v1 = 0 when a=0 means that the photon is absorbed, transferring all of its energy to the mirror. This limit comes from either the m-> 0, for a massless mirror, or v1-> inf for a photon with infinite frequency. The example I used before had a as about 450,000 and gave 0.999997 as a result: http://www.wolframalpha.com/input/?i=sqrt%28+a^2+%2B+4*a+%2B+1%29+-a-1%2C+a+%3D+1e-35*9e16%2F+%286.626e-34*3e9+%29My ability to take limits correctly seems non-existent this morning, but the limit as a-> inf should be 1, and the function is monotonic for a >0, meaning that for a> 0 it will always be between 0 and 1. This can be seen on the graph here: http://www.wolframalpha.com/input/?i=sqrt%28+a^2+%2B+4*a+%2B+1%29+-a-1*If the links don't work right for you, try pasting them directly or seeing if you got a message about cross site scripting. When I click on the links, firefox deletes all of the + and - and () from the equation.
Detection of the extraordinary transverse pressure in optical fieldshttp://metaconferences.org/ocs/public/conferences/9/pdf/3204.pdf
Note that most of the post was referring to an open system where only one mirror is attached to the vehicle. If this explains EM drive thrust, the Q factor that matters would be between the device and the chamber walls. Still, assuming there is some new physics behind the EM drive, similar calculations would probably apply.
Quote from: TheTraveller on 08/05/2015 12:26 pmOld sailors trick.Use 0.25m long pieces of old cassette tape. Very low mass but high surface area.What I expect to see is air being thrown outward from the rotating table and being drawn up from the floor and down from the roof to make up for the air being thrown outward.Wouldn't those potentially respond magnetically as well as via air currents? Of course, any plastic type material like that will respond to electrical/static buildup (think old-fashioned christmas-tree icicles) so may not be giving the sort of result you want if you're looking for just air currents.
Has anyone heard of the experiments performed by David Pares? http://www.paresspacewarpresearch.org/index.htmLooks like he is measuring forces from a fractal tripole array. I haven't scrutinized his pages very thoroughly yet, but at first glance his numbers seem 'too good to be true'. But maybe an asymmetric warp bubble could be responsible for all EM Drive forces observed? https://forum.nasaspaceflight.com/index.php?topic=36313.msg1362403#msg1362403
Since when did Eagleworks have 100W of Rf to fill a frustum with?
Quote from: deltaMass on 08/06/2015 08:11 amQuote from: meberbs on 08/06/2015 06:13 amv2/v1 = sqrt(a^2 + 4*a +1)-a-1, where a=m*c^2/(h*v1)where v2 is the new frequency, v1 is the starting frequency, m is the mass of the mirror that the photon reflects off, h and c are the usual constants.The formula is fine when a=0, because then v2/v1=0 as expected.But when a >1 (the macroscopic case we have here), v2/v1 >1 also, which seems to make no sense.I think you are filling in some numbers wrong. v2/v1 = 0 when a=0 means that the photon is absorbed, transferring all of its energy to the mirror. This limit comes from either the m-> 0, for a massless mirror, or v1-> inf for a photon with infinite frequency. The example I used before had a as about 450,000 and gave 0.999997 as a result: http://www.wolframalpha.com/input/?i=sqrt%28+a^2+%2B+4*a+%2B+1%29+-a-1%2C+a+%3D+1e-35*9e16%2F+%286.626e-34*3e9+%29My ability to take limits correctly seems non-existent this morning, but the limit as a-> inf should be 1, and the function is monotonic for a >0, meaning that for a> 0 it will always be between 0 and 1. This can be seen on the graph here: http://www.wolframalpha.com/input/?i=sqrt%28+a^2+%2B+4*a+%2B+1%29+-a-1*If the links don't work right for you, try pasting them directly or seeing if you got a message about cross site scripting. When I click on the links, firefox deletes all of the + and - and () from the equation.
Quote from: TheTraveller on 08/06/2015 04:00 pmSince when did Eagleworks have 100W of Rf to fill a frustum with? I found this picture on a google image search. Didn't notice the power level. Perhaps it is just a simulation? I was simply relating the two field geometries, wondering if there is anything to Pares' experiments.
Quote from: aero on 08/06/2015 04:13 amQuote from: rfcavity on 08/06/2015 03:43 amWhat mesh grid size are you guys using for those meep sims? It seems like more of a stepped cylinder than a tapered cavity, or is that intended?The lattice is 0.2747255683428571 meters longOh please.
Quote from: rfcavity on 08/06/2015 03:43 amWhat mesh grid size are you guys using for those meep sims? It seems like more of a stepped cylinder than a tapered cavity, or is that intended?The lattice is 0.2747255683428571 meters long
What mesh grid size are you guys using for those meep sims? It seems like more of a stepped cylinder than a tapered cavity, or is that intended?
Quote from: deltaMass on 08/06/2015 06:56 amQuote from: aero on 08/06/2015 04:13 amQuote from: rfcavity on 08/06/2015 03:43 amWhat mesh grid size are you guys using for those meep sims? It seems like more of a stepped cylinder than a tapered cavity, or is that intended?The lattice is 0.2747255683428571 meters longOh please.To 16 significant digits.
Quote from: aero on 08/06/2015 05:56 pmQuote from: deltaMass on 08/06/2015 06:56 amQuote from: aero on 08/06/2015 04:13 amQuote from: rfcavity on 08/06/2015 03:43 amWhat mesh grid size are you guys using for those meep sims? It seems like more of a stepped cylinder than a tapered cavity, or is that intended?The lattice is 0.2747255683428571 meters longOh please.To 16 significant digits.Which in this context means down to roughly one millionth the diameter of an atom. So again - perleez!